-16x+300=0.03x^2-0.4x+28

Solution for -16x+300=0.03x^2-0.4x+28 equation:

-16x+300=0.03x^2-0.4x+28

We move all terms to the left:

-16x+300-(0.03x^2-0.4x+28)=0

We get rid of parentheses

-0.03x^2-16x+0.4x-28+300=0

We add all the numbers together, and all the variables

-0.03x^2-15.6x+272=0

a = -0.03; b = -15.6; c = +272;
Δ = b2-4ac
Δ = -15.62-4·(-0.03)·272
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.6)-2\sqrt{69}}{2*-0.03}=\frac{15.6-2\sqrt{69}}{-0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.6)+2\sqrt{69}}{2*-0.03}=\frac{15.6+2\sqrt{69}}{-0.06}
$